Lesson Video Writing Four Digit Numbers In Various Forms Nagwa Sorting the list of number's digits and getting the 1st and 2nd biggest digits will give you at best o(n * log n) time complexity (assuming you will use quick sort). you can achieve somewhat better performance if you will use another approach: partition (reorder) your array (as in quick sort), so you'll have a pivot value which divides your array in two parts: those which are less than pivot. Program in c. code: *write a c program to find 2nd largest digit in a given number. or write a program to find 2nd largest digit in a given number using c* . #include<stdio.h>. int main () {. int num, reminder, largest= 0,sec largest=0; printf ("enter the number :"); scanf ("%d",&num);.
Example 11 Find The Greatest 4 Digit Number Which Is A Perfect Questions and answers on comparing and arranging numbers: i. circle the smallest and tick ( ) the largest in the given sets: (i) 7920 8209 6305 5706 4321. (ii) 5248 2990 3841 4801 6549. (iii) 3832 5042 8700 9354 4672. (iv) 1832 2832 3845 2700 6840. (v) 7548 4241 3975 9410 6942. (vi) 4421 3785 9441 8961 7265. About press copyright contact us creators advertise developers terms privacy policy & safety how works test new features nfl sunday ticket press copyright. Given a list of numbers, the task is to write a python program to find the second largest number in the given list. examples: input: list1 = [10, 20, 4] output: 10. input: list2 = [70, 11, 20, 4, 100] output: 70. method 1: sorting is an easier but less optimal method. given below is an o (n) algorithm to do the same. When you get a new largest number, the old largest number become the second largest number. so all you need is a single check for the largest number, and two assignments. something like. largest2 = largest; largest = number; you still need to check for numbers larger than largest2.
Python Program To Find The 2nd Largest Digit In A Given Number Btech Given a list of numbers, the task is to write a python program to find the second largest number in the given list. examples: input: list1 = [10, 20, 4] output: 10. input: list2 = [70, 11, 20, 4, 100] output: 70. method 1: sorting is an easier but less optimal method. given below is an o (n) algorithm to do the same. When you get a new largest number, the old largest number become the second largest number. so all you need is a single check for the largest number, and two assignments. something like. largest2 = largest; largest = number; you still need to check for numbers larger than largest2. The greatest number is 87,642. rule iii: if zero is one of the digits while forming the smaller number, it is written in place after the highest place. example: using the digits 7, 2, 3, 0 and 5, write the smallest number. solution: the smallest number is 20,357. write the smallest number and the greatest number using the digits 4, 3, 3, 8 and 7. Here, 9 > 6 > 5 > 4 > 3 >2. so, the greatest 6 digit number formed using these digits is 9,65,432. so, the smallest 6 digit number formed using these digits is 2,34,569. but, if we have one of the given digits as 0, then it is not written at the extreme left. while writing the smallest number, we write 0 in the second place from the left.
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