The Number Of Gram Molecules Of Oxygen In 6 02 10 24 Co Molecules Is

The Number Of Gram Molecules Of Oxygen In6 02 г 10 24ођ The number of gram molecules of oxygen in 6.02*10^24 co molecules is. view solution. Solution. 1 mole co equivalent to 6.02x10^23 molecules of co contain 6.02x10^23 atoms of oxygen. so 6.02x10^24 co molecules contain 6.02x10^24 atoms of o which is equivalent to 10 gm atoms of oxygen. since oxygen is diatomic, 10 g atom = 1 2x10 g molecule of oxygen = 5 gram molecule of o2 = 5 grams of o2 molecule. or in simple terms,.

The Number Of Gram Molecules Of Oxygen In 6 02 г 10 24о The number of gram molecules of oxygen in 6.02×10^24 co molecule ismole concept full chapter : playlist?list=plnnjws9bnuacttg ueoenwb7m9. The number of gram atoms of oxygen in 6.02 × 10 24 c o molecules is obtained by dividing 6.02 × 10 24 with avogadro's number. 6.02 × 10 24 6.02 × 10 23 = 10 . the number of gram molecules of oxygen ( o 2 ) is equal to one half the number of gram atoms of oxygen. The number of gram molecules of oxygen in 6.02 x 1024 co molecules is (a) 10 g molecules (b) 5 g (c) 1 g molecules (d) 0.5 g molecules. live course for free. Now the number of gram atoms in $ 6.02 \times {10^{24}} $ $ co $ molecules will be $ \dfrac{{6.02 \times {{10}^{24}}}}{{6.02 \times {{10}^{23}}}} = 10 $ the number of gram molecules of oxygen in $ 6.02 \times {10^{24}} $ carbon monoxide molecule is $ \dfrac{{10}}{2} = 5 $ because one oxygen molecule is made of two atoms of oxygen. hence the.